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Dog Age Calculator #90

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Dog Age Calculator #90

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16 changes: 16 additions & 0 deletions Dog Age Calculator (by AdyaTech)/dogage.py
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Original file line number Diff line number Diff line change
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# Request input from the user to provide a dog's age in human years and convert it to an integer
h_age = int(input("Input a dog's age in human years: "))

# Check if the entered age is less than zero; if true, display an error message and exit the program
if h_age < 0:
print("Age must be a positive number.")
exit()
# If the entered age is 2 years or less, calculate the dog's age in dog's years using the formula 10.5 times the human years
elif h_age <= 2:
d_age = h_age * 10.5
# For ages greater than 2, calculate the dog's age in dog's years using the formula 21 plus 4 times the remaining human years after 2
else:
d_age = 21 + (h_age - 2) * 4

# Display the calculated dog's age in dog's years
print("The dog's age in dog's years is", d_age)
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@iamwatchdogs iamwatchdogs May 20, 2026

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  • Don't add too many comments; code should be self-documenting
  • Check for valid input
  • If the script fails due to unexpected behaviours, then it should exit with a non-zero code.
  • The ternary operator is just a preference
Suggested change
# Request input from the user to provide a dog's age in human years and convert it to an integer
h_age = int(input("Input a dog's age in human years: "))
# Check if the entered age is less than zero; if true, display an error message and exit the program
if h_age < 0:
print("Age must be a positive number.")
exit()
# If the entered age is 2 years or less, calculate the dog's age in dog's years using the formula 10.5 times the human years
elif h_age <= 2:
d_age = h_age * 10.5
# For ages greater than 2, calculate the dog's age in dog's years using the formula 21 plus 4 times the remaining human years after 2
else:
d_age = 21 + (h_age - 2) * 4
# Display the calculated dog's age in dog's years
print("The dog's age in dog's years is", d_age)
try:
human_years = float(input("Input a dog's age in human years: "))
except ValueError:
print("Please enter a valid number")
exit(1)
if human_years < 0:
print("Age must be a positive number.")
exit(1)
dog_age = human_years * 10.5 if human_years <= 2 else 21 + (human_years - 2) * 4
print("The dog's age in dog's years is", dog_age)

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