diff --git a/exercises/practice/eliuds-eggs/.approaches/config.json b/exercises/practice/eliuds-eggs/.approaches/config.json
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+{
+  "introduction": {
+    "authors": ["yrahcaz7"],
+    "contributors": []
+  },
+  "approaches": [
+    {
+      "uuid": "27fb20ed-a4c2-4f73-a8fc-86ba384c7b35",
+      "slug": "parameter-modification",
+      "title": "Modify the Parameter in a Loop",
+      "blurb": "Modify the parameter in a while-loop to calculate the number of eggs.",
+      "authors": ["yrahcaz7"]
+    },
+    {
+      "uuid": "65fd717c-0e50-444b-a4b2-b51862f1f810",
+      "slug": "no-parameter-modification",
+      "title": "Loop Without Modifying the Parameter",
+      "blurb": "Loop over the bits without modifying the parameter to determine the number of eggs.",
+      "authors": ["yrahcaz7"]
+    }
+  ]
+}
diff --git a/exercises/practice/eliuds-eggs/.approaches/introduction.md b/exercises/practice/eliuds-eggs/.approaches/introduction.md
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+# Introduction
+
+There are many Pythonic approaches to solving the Eliud's Eggs exercise:
+
+- Using a `while-loop`, modifying the parameter on each iteration
+- Looping over every binary digit _without_ modifying the parameter
+- Converting the `int` to a binary string and counting the ones
+
+There are also some approaches that aren't recommended:
+
+- Using the bit-count functionality from the Python standard library, as the instructions forbid it
+- Breaking up the proccess into many functions, overcomplicating the solution
+
+
+## General guidance
+
+The goal of the Eliud's Eggs exercise is to count the number of ones in the binary representation of a number.
+In essence, this requires you to loop over each bit (binary digit) of the number in some way.
+
+The approaches below represent categories of the most common ways of accomplishing this.
+
+
+## Approach: Modifying the Parameter in a `while-loop`
+
+```python
+def egg_count(display_value):
+    eggs = 0
+    while display_value:
+        eggs += display_value % 2
+        display_value //= 2
+    return eggs
+```
+
+This approach uses a `while-loop` to count up all of the ones.
+In the loop, we increment `eggs` by `display_value % 2`.
+This adds the least significant bit (the rightmost digit in the binary representation) of `display_value` to `eggs`.
+
+Next, we divide `display_value` by `2`, discarding any remainder.
+This essentially removes the least significant bit of `display_value`, setting up `display_value` for processing the next bit.
+
+The loop repeats until `display_value` reaches `0` (which indicates that we have no more bits to check), and then we return `eggs`.
+
+To see more variations of this solution, see the [modify the parameter in a loop][approach-parameter-modification] approach.
+
+
+## Approach: Looping Without Modifying the Parameter
+
+```python
+from math import ceil, log2
+
+def egg_count(display_value):
+    eggs = 0
+    for bit_position in range(ceil(log2(display_value + 1))):
+        eggs += (display_value >> bit_position) & 1
+    return eggs
+```
+
+This solution uses a `for-loop` with `range()` to iterate over all of the bits in `display_value`.
+To determine how many bits `display_value` has, this solution imports `ceil` and `log2` from the `math` module.
+It then feeds this number into `range()` to make the `for-loop` iterate over all the `bit_position`s.
+
+For each `bit_position`, we determine the value of the bit at that position by using the [right-shift operator][right-shift-operator] and the bitwise AND operator.
+Once we determine the bit's value, we increment `eggs` by that number.
+
+After the loop ends, we know that we have checked all of the bits in `display_value`, thus we return `eggs`.
+
+For more details and variations, read the [loop without modifying the parameter][approach-no-parameter-modification] approach.
+
+
+[approach-parameter-modification]: https://exercism.org/tracks/python/exercises/eliuds-eggs/approaches/parameter-modification
+[approach-no-parameter-modification]: https://exercism.org/tracks/python/exercises/eliuds-eggs/approaches/no-parameter-modification
+[right-shift-operator]: https://www.geeksforgeeks.org/software-engineering/right-shift-operator-in-programming/
diff --git a/exercises/practice/eliuds-eggs/.approaches/no-parameter-modification/content.md b/exercises/practice/eliuds-eggs/.approaches/no-parameter-modification/content.md
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+# Loop Without Modifying the Parameter
+
+```python
+from math import ceil, log2
+
+def egg_count(display_value):
+    eggs = 0
+    for bit_position in range(ceil(log2(display_value + 1))):
+        eggs += (display_value >> bit_position) & 1
+    return eggs
+```
+
+This approach uses a loop with `range()` to iterate over all of the bits in `display_value`.
+
+To determine how many bits `display_value` has, this solution imports `ceil` and `log2` from the `math` module.
+We then calculate the base 2 logarithm of `display_value` (plus 1) and round it up.
+(Rounding up is neccessary because `range(<stop>)` excludes the value of `<stop>` from its returned values.)
+
+Once we have the bit length of `display_value`, we feed this number into `range()` to make the `for-loop` iterate over all of `display_value`'s `bit_position`s.
+
+For each `bit_position`, we determine the value of the bit at that position by using the [right-shift operator][right-shift-operator] and the bitwise AND operator.
+We do this by right-shifting `display_value` by `bit_position`, making the bit at `bit_position` become the least significant bit.
+Then we use the bitwise AND operator with `1` to remove all bits that are not the least significant bit.
+
+~~~~exercism/note
+You could also calculate the bit's value by using arithmetic operators instead of bitwise ones:
+
+```python
+eggs += (display_value // (2 ** bit_position)) % 2
+```
+~~~~
+
+Once we determine the bit's value, we increment `eggs` by that number.
+
+After the loop ends, we know that we have checked all of the bits in `display_value`, thus we return `eggs`.
+
+
+## Variation #1: Using an `if` Statement
+
+```python
+from math import ceil, log2
+
+def egg_count(display_value):
+    eggs = 0
+    for bit_position in range(ceil(log2(display_value + 1))):
+        if display_value & (1 << bit_position):
+            eggs += 1
+    return eggs
+```
+
+In this variant, the loop uses an `if` statement to check if the digit at `display_value` is `1`.
+
+
+## Variation #2: Using `sum()` with a Generator Expression
+
+```python
+from math import ceil, log2
+
+def egg_count(display_value):
+    return sum(
+        (display_value >> bit_position) & 1
+        for bit_position in range(ceil(log2(display_value + 1)))
+    )
+```
+
+This variant is actually a one-liner, it is just split up here for readability.
+Here, we replace the `for-loop` with a [generator expression][generator-expression] and use `sum()` to collect the values into the result.
+
+
+## Variation #3: Manually Tracking the Place Value
+
+```python
+def egg_count(display_value):
+    eggs = 0
+    place_value = 1
+    while place_value <= display_value:
+        if display_value & place_value:
+            eggs += 1
+        place_value <<= 1
+    return eggs
+```
+
+This variant avoids `import`s by manually tracking the `place_value` of the current bit position.
+This way, the `while-loop` can end when `place_value` becomes greater than `display_value`.
+
+The operations in the loop are rather similar to the "using an `if` statement" variant.
+The main differences are not having to calculate the `place_value` from the bit position, and having to manually progress the iteration by left-shifting `place_value` by `1` (which is the same as multiplying `place_value` by `2`).
+
+
+[generator-expression]: https://dbader.org/blog/python-generator-expressions
+[right-shift-operator]: https://www.geeksforgeeks.org/software-engineering/right-shift-operator-in-programming/
diff --git a/exercises/practice/eliuds-eggs/.approaches/no-parameter-modification/snippet.txt b/exercises/practice/eliuds-eggs/.approaches/no-parameter-modification/snippet.txt
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+from math import ceil, log2
+
+def egg_count(display_value):
+    eggs = 0
+    for bit_position in range(ceil(log2(display_value + 1))):
+        eggs += (display_value >> bit_position) & 1
+    return eggs
\ No newline at end of file
diff --git a/exercises/practice/eliuds-eggs/.approaches/parameter-modification/content.md b/exercises/practice/eliuds-eggs/.approaches/parameter-modification/content.md
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+# Modify the Parameter in a Loop
+
+```python
+def egg_count(display_value):
+    eggs = 0
+    while display_value:
+        eggs += display_value % 2
+        display_value //= 2
+    return eggs
+```
+
+This approach uses a `while-loop` to count up all of the ones.
+In the loop, we increment `eggs` by `display_value % 2`.
+This adds the least significant bit (the rightmost digit in the binary representation) of `display_value` to `eggs`.
+
+Next, we divide `display_value` by `2`, discarding any remainder.
+This essentially removes the least significant bit of `display_value`, setting up `display_value` for processing the next bit.
+
+The loop repeats until `display_value` reaches `0` (which indicates that we have no more bits to check), and then we return `eggs`.
+
+
+## Variation #1: Using Boolean Operators
+
+```python
+def egg_count(display_value):
+    eggs = 0
+    while display_value > 0:
+        if display_value % 2 == 1:
+            eggs += 1
+        display_value //= 2
+    return eggs
+```
+
+This is essentially just a more verbose formulation of the previous version.
+Instead of relying on Python converting `int`s to `bool`s, this solution manually compares `display_value` to `0`.
+It also uses an `if` statement to check if `eggs` should be incremented by `1`, instead of directly using the result of `display_value % 2`.
+
+Even though this variant is more verbose than the others, some may consider it to be more readable.
+
+
+## Variation #2: Using Bitwise Operators
+
+```python
+def egg_count(display_value):
+    eggs = 0
+    while display_value > 0:
+        eggs += display_value & 1
+        display_value >>= 1
+    return eggs
+```
+
+This variant replaces the modulo (`%`) and floor division (`//`) with [bitwise operators][bitwise-operators].
+`&` is the bitwise AND operator, which results in a number whose binary representation only has ones where _both_ of its arguments has ones.
+(All other bits are zeros.)
+
+For example, if we used the numbers `3` (`11` in binary) and `1` (`1` in binary), we get `1`:
+
+```python
+0b011 & 0b001
+#=> 0b001
+```
+
+This is because the only bit in both numbers that is `1` is least significant bit.
+This property lets us extract the least significant bit of `display_value` by using `display_value & 1`.
+
+For the next step, we use `>>`, the [right-shift operator][right-shift-operator].
+The expression `a >> b` shifts all of `a`'s bits to the right by `b` places, and returns the resulting number.
+
+For example, if we used the numbers `5` (`101` in binary) and `1`, we get `2` (`10` in binary):
+
+```python
+0b101 >> 1
+#=> 0b010
+```
+
+You can see how `& 1` and `>>= 1` perform the same function as the `% 2` and `//= 2` used in earier variants.
+
+
+[bitwise-operators]: https://www.w3schools.com/programming/prog_operators_bitwise.php
+[right-shift-operator]: https://www.geeksforgeeks.org/software-engineering/right-shift-operator-in-programming/
diff --git a/exercises/practice/eliuds-eggs/.approaches/parameter-modification/snippet.txt b/exercises/practice/eliuds-eggs/.approaches/parameter-modification/snippet.txt
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+def egg_count(display_value):
+    eggs = 0
+    while display_value:
+        eggs += display_value % 2
+        display_value //= 2
+    return eggs
\ No newline at end of file